President Trump Announces Executive Order to Protect Babies Who Survive Abortions
On Wednesday, President Trump spoke at the National Catholic Prayer Breakfast, where he announced that he will sign a “born alive” executive order that will protect babies who survive botched abortions.
According to the Washington Examiner, although he did not specify the order’s details, Trump said that “I will always protect the vital role of religion and prayer in American society, and I will always defend the sacred right to life,” and that his order will “ensure that all precious babies born alive, no matter their circumstances, receive the medical care that they deserve.”
The Examiner continues:
Born-alive measures have been one of the pillars of anti-abortion advocacy for nearly 20 years. President George W. Bush signed the Born-Alive Infants Protection Act in 2002 after it passed in the Senate by unanimous consent. The bill made survivors of abortion federally protected persons.
Nebraska Sen. Ben Sasse in 2017 introduced a more robust version of the bill, which would impose criminal penalties on doctors who fail to provide abortion survivors with medical care. Sasse has introduced the bill several times since, but has not been able to secure significant bipartisan support for it. In April 2019, Hawaii Sen. Mazie Hirono condemned the bill as a “threat to women’s reproductive health.”
Sasse called Trump’s announcement a “step in the right direction” and told the Washington Examiner that Congress should follow it up by passing his version of the bill.
“This is really simple: every baby deserves a fighting chance,” Sasse said in a statement. “Whether she’s born in a state-of-the-art NICU or an abortion clinic in a strip mall, these babies deserve medical care and dignity.”
Abortion is one of, if not the biggest, tragic evils of our time. And there is no question that leaving the survivor of a botched abortion to die is clear murder. Thank you, President Trump, for this decision.